Now, considering the code, maybe the user wants to enter values interactively. So:
Now, considering the user might not know the exact formula, the code should have explanations about how the calculation works. So in the code comments or in the help messages. holeinonepangyacalculator 2021
simulate_more = input("Simulate multiple attempts? (y/n): ").lower() if simulate_more == 'y': attempts = int(input("How many attempts to simulate? ")) sim_success = simulate_attempts(chance, attempts) print(f"\nOut of {attempts} attempts, you hit a Hole-in-One {sim_success} times.") def calculate_hole_in_one_chance(distance, club_power, wind_effect, accuracy, skill_bonus): effective_distance = distance + wind_effect power_diff = abs(club_power - effective_distance) base_chance = max(0, (100 Now, considering the code, maybe the user wants
Once the probability is calculated, the user might want to simulate, say, 1000 attempts to get the expected success rate (like, on average, how many attempts are needed). simulate_more = input("Simulate multiple attempts
Another angle: Maybe the Hole-in-One in Pangya is based on a hidden value, and the calculator uses player stats to estimate chance. For example, using club type's skill level, player's overall level, and game modifiers.
But since the user wants a 2021 version, perhaps there's an update in the game's mechanics compared to previous years. However, without specific info, I'll proceed with a plausible formula.